JEE Mains · Physics · STD 12 - 13. Nuclei
The mass number of nucleus having radius equal to half of the radius of nucleus with mass number \(192\) is _______.
- A \(24\)
- B \(32\)
- C \(40\)
- D \(20\)
Answer & Solution
Correct Answer
(A) \(24\)
Step-by-step Solution
Detailed explanation
\(R_1=\frac{R_2}{2}\) \(R_0\left(A_1\right)^{1 / 3}=\frac{R_0}{2}\left(A_2\right)^{1 / 3}\) \(A_1=\frac{1}{8} A_2\) \(A_1=\frac{192}{8}=24\)
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