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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2019
  • Hard
  • MCQ

The output of the given logic circuit is

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Answer & Solution

Correct Answer

(C) \(A\bar B\)

Step-by-step Solution

Detailed explanation

\(Y =A \cdot \overline{A B}+A B \cdot \bar{B}\)

\(=A \cdot(\bar{A}+\bar{B})+(A B) \cdot \bar{B} \)

\(=A \bar{B}+0\)

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