JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
- JEE Mains 2022
- Medium
- Numerical
A steam engine intakes \(50\, g\) of steam at \(100^{\circ} C\) per minute and cools it down to \(20^{\circ} C\). If latent heat of vaporization of steam is \(540 \,cal g ^{-1}\), then the heat rejected by the steam engine per minute is .........\(\times 10^{3}\)\(cal.\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(31\)
Step-by-step Solution
Detailed explanation
Heat rejected \(= mL _{ f }+ mS \Delta T\)
\(=(50 \times 540)+50(1)(100-20)\)
\(=31000 Cal\)
\(=31 \times 10^{3} Cal\)
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