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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2020
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In a Young's double slit experiment, the separation between the slits is \(0.15\; \mathrm{mm}\). In the experiment, a source of light of wavelength \(589 \;\mathrm{nm}\) is used and the interference pattern is observed on a screen kept \(1.5\; \mathrm{m}\) away. The separation between the successive bright fringes on the screen is......\(mm\)

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Answer & Solution

Correct Answer

(B) \(5.9\)

Step-by-step Solution

Detailed explanation

Finge width, \(\beta=\frac{\mathrm{D} \lambda}{\mathrm{d}}=\frac{1.5 \times 589 \times 10^{-9}}{0.15 \times 10^{-3}}\)

\(=5.9 \times 10^{-3} \mathrm{m}\)

\(=5.9 \mathrm{mm}\)

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