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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2019
  • Medium
  • MCQ

A plano-convex lens (focal length \(f_2,\) refractive index \(\mu _2,\) radius of curvature \(R\) ) fits exactly into a plano-concave lens (focal length \(f_1,\) refractive index \(\mu _1,\) radius of curvature \(R\) ). Their plane surfaces are parallel to each other. Then, the focal length of the combination will be

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Answer & Solution

Correct Answer

(B) \(\frac{R}{{{\mu _2} - {\mu _1}}}\)

Step-by-step Solution

Detailed explanation

\(\frac{1}{f}=\frac{\left(\mu_{1}-1\right)}{R}+\frac{\left(1-\mu_{2}\right)}{R}\)

\(\frac{1}{f}=\frac{\left(\mu_{1}-\mu_{2}\right)}{R}\)

\(\Rightarrow \quad \mathrm{f}=\frac{\mathrm{R}}{\mu_{1}-\mu_{2}}\)

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