JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2019
- Medium
- MCQ
A plano-convex lens (focal length \(f_2,\) refractive index \(\mu _2,\) radius of curvature \(R\) ) fits exactly into a plano-concave lens (focal length \(f_1,\) refractive index \(\mu _1,\) radius of curvature \(R\) ). Their plane surfaces are parallel to each other. Then, the focal length of the combination will be
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(\frac{R}{{{\mu _2} - {\mu _1}}}\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{f}=\frac{\left(\mu_{1}-1\right)}{R}+\frac{\left(1-\mu_{2}\right)}{R}\)
\(\frac{1}{f}=\frac{\left(\mu_{1}-\mu_{2}\right)}{R}\)
\(\Rightarrow \quad \mathrm{f}=\frac{\mathrm{R}}{\mu_{1}-\mu_{2}}\)
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