JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2019
- Medium
- Numerical
A resonance tube is old and has jagged end. It is still used in the laboratory to determine velocity of sound in air. A tuning fork of frequency \(512\,Hz\) produces first resonance when the tube is filled with water to a mark \(11\,cm\) below a reference mark, near the open end of the tube. The experiment is repeated with another fork of frequency \(256\,Hz\) which produces first resonance when water reaches a mark \(27\,cm\) below the reference mark. The velocity of sound in air, obtained in the experiment, is close to .... \(ms^{-1}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(328\)
Step-by-step Solution
Detailed explanation
\(\lambda_{1}=4(11+\mathrm{e}) =\frac{\mathrm{v}}{512}\)
\(\lambda_{2}=4(27+e)=\frac{V}{256}\)
\(\frac{11+e}{27+e}=\frac{1}{2}\)
\(\Rightarrow \quad 22+2 e=27+e\)
\(\Rightarrow \quad e=5\)
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