JEE Mains · Physics · STD 11 - 13. oscillations
The motion of a simple pendulum excuting \(S.H.M\). is represented by following equation. \(Y = A \sin (\pi t +\phi)\), where time is measured in \(second\). The length of pendulum is .............\(cm\)
- A \(97.23\)
- B \(25.3\)
- C \(99.4\)
- D \(406.1\)
Answer & Solution
Correct Answer
(C) \(99.4\)
Step-by-step Solution
Detailed explanation
\(\omega=\sqrt{\frac{ g }{\ell}}=\pi\) \(\frac{ g }{\ell}=\pi^{2} \Rightarrow \ell=\frac{ g }{\pi^{2}}\) \(\ell=\frac{980}{\pi^{2}} \approx 99.4 \,cm\)
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