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JEE Mains · Physics · STD 11 - Oscillations
  • JEE Mains 2022
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  • MCQ

The motion of a simple pendulum excuting \(S.H.M\). is represented by following equation. \(Y = A \sin (\pi t +\phi)\), where time is measured in \(second\). The length of pendulum is .............\(cm\)

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Answer & Solution

Correct Answer

(C) \(99.4\)

Step-by-step Solution

Detailed explanation

\(\omega=\sqrt{\frac{ g }{\ell}}=\pi\)

\(\frac{ g }{\ell}=\pi^{2} \Rightarrow \ell=\frac{ g }{\pi^{2}}\)

\(\ell=\frac{980}{\pi^{2}} \approx 99.4 \,cm\)

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