JEE Mains · Physics · STD 11- Mechanical properties of solids
- JEE Mains 2026
- Easy
- MCQ
Two wires \(A\) and \(B\) made of different materials of length 6.0 cm and 5.4 cm, respectively and area of cross sections \(3.0 \times 10^{-5} m^2\) and \(4.5 \times 10^{-5} m^2\), respectively are stretched by the same magnitude under a given load. The ratio of the Young's modulus of \(A\) to that of \(B\) is \(x : 3\). The value of x is ___________.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) 5
Step-by-step Solution
Detailed explanation
\(T =\frac{ F / A }{\Delta \ell / \ell} \Rightarrow Y =\frac{ F \ell}{ A \Delta \ell}\)
\(\frac{Y_{A}}{Y_{B}} = \frac{l_{A}}{l_{B}} (\frac{A_{B}}{A_{A}})\)
\(= \frac{6}{5.4} (\frac{4.5 \times 10^{-5}}{3 \times 10^{-5}}) = \frac{9}{5.4} = \frac{5}{3}\)\(\Rightarrow \frac{x}{3} = \frac{5}{3}\)
\(\Rightarrow x = 5\)
\(\frac{Y_{A}}{Y_{B}} = \frac{l_{A}}{l_{B}} (\frac{A_{B}}{A_{A}})\)
\(= \frac{6}{5.4} (\frac{4.5 \times 10^{-5}}{3 \times 10^{-5}}) = \frac{9}{5.4} = \frac{5}{3}\)\(\Rightarrow \frac{x}{3} = \frac{5}{3}\)
\(\Rightarrow x = 5\)
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