JEE Mains · Physics · STD 11 - Motion in plane
- JEE Mains 2019
- Medium
- Numerical
The stream of a river is flowing with a speed of \(2\,km/h.\) A swimmer can swim at a speed of \(4\,km/h.\) ....... \(^o\) should be the direction of the swimmer with respect to the flow of the river to cross the river straight .
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(120\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{l}
For\,swimmer\,to\,cross\,the\,river\,straight\\
\Rightarrow \,\,\,\,\,4\,\sin \,\theta = 2\\
\Rightarrow \,\,\,\,\,\sin \,\theta \, = \frac{1}{2}\, \Rightarrow \,\theta \, = {30^ \circ }\\
So,\,angle\,with\,direction\,of\,river\,flow\,\\
= {90^ \circ } + \theta = {120^ \circ }.
\end{array}\)

For\,swimmer\,to\,cross\,the\,river\,straight\\
\Rightarrow \,\,\,\,\,4\,\sin \,\theta = 2\\
\Rightarrow \,\,\,\,\,\sin \,\theta \, = \frac{1}{2}\, \Rightarrow \,\theta \, = {30^ \circ }\\
So,\,angle\,with\,direction\,of\,river\,flow\,\\
= {90^ \circ } + \theta = {120^ \circ }.
\end{array}\)

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