JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
Light enters from air into a given medium at an angle of \(45^{\circ}\) with interface of the air-medium surface. After refraction, the light ray is deviated through an angle of \(15^{\circ}\) from its original direction. The refractive index of the medium is.
- A \(1.732\)
- B \(1.333\)
- C \(1.414\)
- D \(2.732\)
Answer & Solution
Correct Answer
(C) \(1.414\)
Step-by-step Solution
Detailed explanation
\(i=45^{\circ}\) \(D=i-r\) \(15^{\circ}=45-r \Rightarrow r=30^{\circ}\) \(n_{1} \sin i=n_{2} \sin r\) \(1 \sin 45^{\circ}=\mu \sin 30^{\circ}\) \(\frac{1}{\sqrt{2}}=\mu \frac{1}{2}\) \(\mu=\sqrt{2}=1.414\)
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