JEE Mains · Physics · STD 11- 8. mechanical properties of solids
The elongation of a wire on the surface of the earth is \(10^{-4} \; m\). The same wire of same dimensions is elongated by \(6 \times 10^{-5} \; m\) on another planet. The acceleration due to gravity on the planet will be \(\dots \; ms ^{-2}\). (Take acceleration due to gravity on the surface of earth \(=10 \; m / s ^{-2}\) )
- A \(0\)
- B \(2\)
- C \(4\)
- D \(6\)
Answer & Solution
Correct Answer
(D) \(6\)
Step-by-step Solution
Detailed explanation
\(\Delta \ell \propto g\) \(\frac{\Delta \ell_{\text {earth }}}{\Delta \ell_{\text {planet }}}=\frac{g_{\text {earth }}}{g_{\text {planet }}}=\frac{10^{-4}}{6 \times 10^{-5}}\) \(g_{planet} = 6 \; m / s ^{-2}\) Ans. \(6.00\)
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