JEE Mains · Physics · STD 11 - 7. gravitation
At what distance above and below the surface of the earth a body will have same weight? (take radius of earth as \(R\).)
- A \(\sqrt{5} \mathrm{R}-\mathrm{R}\)
- B \(\frac{\sqrt{3} R-R}{2}\)
- C \(\frac{R}{2}\)
- D \(\frac{\sqrt{5} \mathrm{R}-\mathrm{R}}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{\sqrt{5} \mathrm{R}-\mathrm{R}}{2}\)
Step-by-step Solution
Detailed explanation
\( g_p=\frac{g R^2}{(R+h)^2} \) \( g_q=g\left(1-\frac{h}{R}\right) \) \( g_p=g_q \) \( \frac{g}{\left(1+\frac{h}{R}\right)^2}=g\left(1-\frac{h}{R}\right) \) \( \left(1-\frac{h^2}{R^2}\right)\left(1+\frac{h}{R}\right)=1\) Take \(\frac{\mathrm{h}}{\mathrm{R}}=\mathrm{x}\) So…
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