JEE Mains · Physics · STD 12 - 10. Wave optics
In a Young double slit experiment, the wavelength of incident light is \(6000\) Å, the separation between slits \(S_1\) and \(S_2\) is \(5\) cm and the distance between slits plane and screen is \(50\) cm, as shown in the figure below. If the resultant intensity at \(P\) is equal to the intensity due to individual slits, the path difference between interfering waves is __________ Å.
- A \(4000\)
- B \(3000\)
- C \(2000\)
- D \(1000\)
Answer & Solution
Correct Answer
(C) \(2000\)
Step-by-step Solution
Detailed explanation
Let the intensity due to each individual slit be \(I_0\). The resultant intensity \(I_R\) at a point where the phase difference is \(\phi\) is given by: \(I_R = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi\) Given that \(I_1 = I_2 = I_0\) and the resultant intensity \(I_R = I_0\), we…
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