JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2019
- Hard
- Numerical
In a double -slit experiment, green light \(\left( {5303\,\mathop A\limits^o } \right)\) falls on a double slit having a separation of \(19.44\,\mu m\) and a width of \(4.05\,\mu m\). The number of bright fringes between the first and the second diffraction minima is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(05\)
Step-by-step Solution
Detailed explanation
For diffraction
Location of \(1^{\text {st }}\) minima
\({y_1} = \frac{{D\lambda }}{a} = 0.2469\,D\lambda \)
Location of \(2^{\text {nd }}\) minima
\({{\text{y}}_2} = \frac{{2{\text{D}}\lambda }}{{\text{a}}} = 0.4938\,{\text{D}}\lambda \)
Now for interference
Path for interference
Path difference at \(P\)
\(\frac{d y}{D}=4.8 \lambda\)
Path difference at \(P\)
\(\frac{d y}{D}=9.6 \lambda\)
So orders of maxima in between \(\mathrm{P}\) and \(\mathrm{Q}\) is
\(5,\,6,\,7,\,8,\,9\)
So \(5\) bright fringes all present between \(\mathrm{P}\) and \(\mathrm{Q}\)
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