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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2019
  • Hard
  • Numerical

In a double -slit experiment, green light \(\left( {5303\,\mathop A\limits^o } \right)\) falls on a double slit having a separation of \(19.44\,\mu m\) and a width of \(4.05\,\mu m\). The number of bright fringes between the first and the second diffraction minima is

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Answer & Solution

Correct Answer

(B) \(05\)

Step-by-step Solution

Detailed explanation

For diffraction

Location of \(1^{\text {st }}\) minima

\({y_1} = \frac{{D\lambda }}{a} = 0.2469\,D\lambda \)

Location of \(2^{\text {nd }}\) minima

\({{\text{y}}_2} = \frac{{2{\text{D}}\lambda }}{{\text{a}}} = 0.4938\,{\text{D}}\lambda \)

Now for interference

Path for interference

Path difference at \(P\)

\(\frac{d y}{D}=4.8 \lambda\)

Path difference at \(P\)

\(\frac{d y}{D}=9.6 \lambda\)

So orders of maxima in between \(\mathrm{P}\) and \(\mathrm{Q}\) is

\(5,\,6,\,7,\,8,\,9\)

So \(5\) bright fringes all present between \(\mathrm{P}\) and \(\mathrm{Q}\)

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