JEE Mains · Maths · STD 11 - 7. binomial theoram
If the ratio of the fifth term from the begining to the fifth term from the end in the expansion of \(\left(\sqrt[4]{2}+\frac{1}{\sqrt[4]{3}}\right)^n\) is \(\sqrt{6}: 1\), then the third term from the beginning is:
- A \(60 \sqrt{2}\)
- B \(60 \sqrt{3}\)
- C \(30 \sqrt{2}\)
- D \(30 \sqrt{3}\)
Answer & Solution
Correct Answer
(B) \(60 \sqrt{3}\)
Step-by-step Solution
Detailed explanation
\(\frac{{ }^{ n } C _4 2^{\frac{ n -4}{4}} \cdot\left(3^{\frac{-1}{4}}\right)^4}{{ }^{ n } C _4 3^{-\left(\frac{ n -4}{4}\right)} \cdot\left(2^{\frac{1}{4}}\right)^4}=\frac{\sqrt{6}}{1}\) \(\Rightarrow n =10\) So…
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