JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2019
- Hard
- MCQ
The time dependence of the position of a particle of mass \(m = 2\) is given by \(\vec r\,(t)\, = \,2t\,\hat i\, - 3{t^2}\hat j\) Its angular momentum with respect to the origin at time \(t = 2\) is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(-48\,\hat k\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow v = 2\hat i - 6 + \hat j\)
\(At\,t = 2\)
\(\overrightarrow v = 2\hat i - 12\hat j\)
\(\overrightarrow p = m\overrightarrow v = 4i - 24\hat j\)
\(At\,t = 2\)
\(\overrightarrow r = 4\hat i - 12\hat j\)
\(\overrightarrow L = \overrightarrow r \times \overrightarrow p = \left| \begin{array}{l}
\hat i\,\,\,\,\,\,\,\,\,\,\hat j\,\,\,\,\,\,\,\,\,\,\,\hat k\\
4\,\,\,\,\,\, - 12\,\,\,\,\,\,\,\,\,0\\
4\,\,\,\,\,\, - 24\,\,\,\,\,\,\,\,\,0
\end{array} \right|\)
\( = \left\{ {4\left( { - 24} \right) + 4 \times 12} \right\}\hat k\)
\( = \left( { - 96 + 48} \right)\hat k\)
\( = \left( - \right)48\,\hat k\)
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