JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
An artillery piece of mass \(M_1\) fires a shell of mass \(\mathrm{M}_2\) horizontally. Instantaneously after the firing, the ratio of kinetic energy of the artillery and that of the shell is _______.
- A \(\mathrm{M}_1 /\left(\mathrm{M}_1+\mathrm{M}_2\right)\)
- B \(\frac{M_2}{M_1}\)
- C \(\mathrm{M}_2 /\left(\mathrm{M}_1+\mathrm{M}_2\right)\)
- D \(\frac{M_1}{M_2}\)
Answer & Solution
Correct Answer
(B) \(\frac{M_2}{M_1}\)
Step-by-step Solution
Detailed explanation
\(\left|\overrightarrow{\mathrm{p}_1}\right|=\left|\overrightarrow{\mathrm{p}_2}\right|\) \(\mathrm{KE}=\frac{\mathrm{p}^2}{2 \mathrm{M}} ; \mathrm{p} \text { same }\) \(\mathrm{KE} \propto \frac{1}{\mathrm{~m}}\)…
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