JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2026
- Easy
- MCQ
The volume of an ideal gas increases 8 times and temperature becomes (1/4) of initial temperature during a reversible change. If there is no exchange of heat in this process (\( \Delta Q=0 \)) then identify the gas from the following options:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) He
Step-by-step Solution
Detailed explanation
\( PV^{\gamma}=constant \)
\( TV^{\gamma-1}=(\frac{T}{4})(8V)^{(\gamma-1)} \)
\( 4=8^{(\gamma-1)} \)
\( 2^{2}=2^{3\gamma-3} \)
\( 2=3(\gamma-1) \)
\( \gamma=\frac{5}{3} \)
Gas is a monoatomic gas.
Answer is He.
\( TV^{\gamma-1}=(\frac{T}{4})(8V)^{(\gamma-1)} \)
\( 4=8^{(\gamma-1)} \)
\( 2^{2}=2^{3\gamma-3} \)
\( 2=3(\gamma-1) \)
\( \gamma=\frac{5}{3} \)
Gas is a monoatomic gas.
Answer is He.
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