JEE Mains · Physics · STD 11- 8. mechanical properties of solids
In an experiment, brass and steel wires of length \(1\,m\) each with areas of cross section \(1\,mm^2\) are used. The wires are connected in series and one end of the combined wire is connected to a rigid support and other end is subjected to elongation. The stress requires to produced a new elongation of \(0.2\,mm\) is [Given, the Young’s Modulus for steel and brass are respectively \(120\times 10^9\,N/m^2\) and \(60\times 10^9\,N/m^2\) ]
- A \(1.8\times 10^6\,N/m^2\)
- B \(0.2\times 10^6\,N/m^2\)
- C \(1.2\times 10^6\,N/m^2\)
- D None of these
Answer & Solution
Correct Answer
(D) None of these
Step-by-step Solution
Detailed explanation
\(\ell = 1\,M\) \(A = {10^{ - 6}}{M^2}\) \(stress = \frac{F}{A}\) \({Y_s} = 120 \times {10^9}\) \(Stress = \frac{{Stress}}{Y}\) \(\Delta \ell = \frac{{\ell \times F}}{{AY}}\)…
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