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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter

In photoelectric effect an em-wave is incident on a metal surface and electrons are ejected from the surface. If the work function of the metal is 2.14 eV and stopping potential is 2 V , what is the wavelength of the em-wave ?
(Given hc \(=1242 \mathrm{eVnm}\) where h is the Planck's constant and c is the speed of light in vaccum.)

  1. A 300 nm
  2. B 400 nm
  3. C 600 nm
  4. D 200 nm
Verified Solution

Answer & Solution

Correct Answer

(A) 300 nm

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \phi=2.14 \\ & V_S=2 \mathrm{~V} \end{aligned}\) Using photoelectric equation. \(\begin{aligned} & \frac{h c}{\lambda}=2.14+2=4.14 \mathrm{eV} \\ & \lambda=\frac{1242}{4.14}=300 \mathrm{~nm} \end{aligned}\)