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JEE Mains · Physics · STD 12 - 12. atoms

The energy levels of an hydrogen atom are shown below. The transition corresponding to emission of shortest wavelength is

  1. A \(C\)
  2. B \(D\)
  3. C \(B\)
  4. D \(A\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(D\)

Step-by-step Solution

Detailed explanation

\(\Delta E =\frac{ hc }{\lambda} \Rightarrow \lambda \alpha \frac{1}{\Delta E }\) For shortest wavelength, energy gap should be maximum. So, correct choice is transition from \(n =3\) to \(n =1\).
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