JEE Mains · Physics · STD 12 - 12. atoms
The energy levels of an hydrogen atom are shown below. The transition corresponding to emission of shortest wavelength is

- A \(C\)
- B \(D\)
- C \(B\)
- D \(A\)
Answer & Solution
Correct Answer
(B) \(D\)
Step-by-step Solution
Detailed explanation
\(\Delta E =\frac{ hc }{\lambda} \Rightarrow \lambda \alpha \frac{1}{\Delta E }\) For shortest wavelength, energy gap should be maximum. So, correct choice is transition from \(n =3\) to \(n =1\).
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