JEE Mains · Physics · STD 11 - 11. thermodynamics
One mole of an ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, \(27\,^oC\).The work done on the gas will be
- A \(300R\,ln\,6\)
- B \(300R\)
- C \(300R\,ln\,7\)
- D \(300R\,ln\,2\)
Answer & Solution
Correct Answer
(D) \(300R\,ln\,2\)
Step-by-step Solution
Detailed explanation
\(Work\,done\,on\,gas = nRT\,\ell n\left( {\frac{{{p_f}}}{{{p_l}}}} \right)\) \( = R\left( {300} \right)\ell n\left( 2 \right)\left( {\frac{{{p_f}}}{{{p_i}}} = 2\,given} \right)\)
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