JEE Mains · Physics · STD 11 - 7. gravitation
Two satellites \(S _{1}\) and \(S _{2}\) are revolving in circular orbits around a planet with radius \(R _{1}=3200 \,km\) and \(R _{2}=800\, km\) respectively. The ratio of speed of satellite \(S_{1}\) to the speed of satellite \(S_{2}\) in their respective orbits would be \(\frac{1}{ x }\) where \(x =\)
- A \(21\)
- B \(25\)
- C \(2\)
- D \(7\)
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
\(V =\sqrt{\frac{ GM }{ r }}\) \(\Rightarrow \frac{ V _{1}}{ V _{2}}=\sqrt{\frac{800}{3200}}=\frac{1}{2}\)
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