JEE Mains · Physics · STD 12 - 12. atoms
The energy levels of an atom is shown is figure. Which one of these transitions will result in the emission of a photon of wavelength \(124.1\,nm\) ?Given \(\left( h =6.62 \times 10^{-34}\,Js \right)\)
- A \(B\)
- B \(A\)
- C \(C\)
- D \(D\)
Answer & Solution
Correct Answer
(D) \(D\)
Step-by-step Solution
Detailed explanation
\(\lambda=\frac{ hc }{\Delta E }\) \(\Delta E _{ A }=2.2\,eV\) \(\Delta E _{ B }=5.2\,eV\) \(\Delta E _{ C }=3\,eV\) \(\Delta E _{ D }=10\,eV\) \(\lambda_{ A }=\frac{6.62 \times 10^{-34} \times 3 \times 10^8}{2.2 \times 1.6 \times 10^{-19}}\)…
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