JEE Mains · Physics · STD 12 - 12. atoms
The energy of \(He ^{+}\)ion in its first excited state is \(......eV\) (The ground state energy for the Hydrogen atom is \(-13.6\,eV )\)
- A \(-3.4\)
- B \(-54.4\)
- C \(-13.6\)
- D \(-27.2\)
Answer & Solution
Correct Answer
(C) \(-13.6\)
Step-by-step Solution
Detailed explanation
\(E _{ n }=\frac{-13.6 Z ^2}{ n ^2}=\frac{-13.6 \times 4}{4}=-13.6\,eV\)
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