JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
Student \(A\) and Student \(B\) used two screw gauges of equal pitch and \(100\) equal circular divisions to measure the radius of a given wire. The actual value of the radius of the wire is \(0.322\, {cm}\). The absolute value of the difference between the final circular scale readings observed by the students \(A\) and \(B\) is .... . [Figure shows position of reference \('O'\) when jaws of screw gauge are closed] Given pitch \(=0.1 \,{cm}\).

- A \(13\)
- B \(26\)
- C \(39\)
- D \(130\)
Answer & Solution
Correct Answer
(A) \(13\)
Step-by-step Solution
Detailed explanation
For \(A\) Reading \(=\) MSR \(+\) CSR \(+\) Error \(0.322=0.300+C S R+5 \times L C\) \(0.322=0.300+C S R+0.005\) \(C S R=0.017\) For \(B\) Reading \(=\) MSR \(+\) CSR \(+\) Error \(0.322=0.200+C S R+0.092\) \(C S R=0.030\) Difference \(=0.030-0.017=0.013 cm\) Division on…
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