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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
If the deBroglie wavelength of an electron is equal to \(10^{-3}\) times the wavelength of a photon of frequency \(6\,\times 10^{14}\,Hz,\) then the speed of electron is equal to: (Speed of light \(=3\times 10^8\,m/s\,;\) Planck’s constant \(=6.63\times 10^{-34}\,J.s\,;\) Mass of electron \(=9.1\times 10^{-31}\,kg\) )
- A \(1.1\times 10^6\,m/s\)
- B \(1.7\times 10^6\,m/s\)
- C \(1.8\times 10^6\,m/s\)
- D \(1.45\times 10^6\,m/s\)
Answer & Solution
Correct Answer
(D) \(1.45\times 10^6\,m/s\)
Step-by-step Solution
Detailed explanation
\({\lambda _e} = {\lambda _{{\text{photon }}}} \times {10^{ - 3}}\) \( \Rightarrow \frac{h}{{mv}} = \frac{c}{v} \times {10^{ - 3}}{\text{s}}\) \( \Rightarrow v = \frac{{hv}}{{mC \times {{10}^{ - 3}}}}\)…
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