JEE Mains · Physics · STD 12 - Atoms
- JEE Mains 2026
- Medium
- MCQ
In hydrogen atom spectrum, (R is Rydberg's constant):
A. the maximum wavelength of the radiation of Lyman series is \(\frac{4}{3 R}\)
B. the Balmer series lies in the visible region of the spectrum
C. the minimum wavelength of the radiation of Paschen series is \(\frac{9}{R}\)
D. the minimum wavelength of Lyman series is \(\frac{5}{4 R}\)
Choose the correct answer from the options given below :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) A, B and C Only
Step-by-step Solution
Detailed explanation
\( \frac{1}{\lambda}=R(1-\frac{1}{4})\)
\(\lambda=\frac{4}{3R} \)
\( \frac{1}{\lambda'}=R(\frac{1}{9})\)
\( \lambda'=\frac{9}{R} \)
\(\lambda=\frac{4}{3R} \)
\( \frac{1}{\lambda'}=R(\frac{1}{9})\)
\( \lambda'=\frac{9}{R} \)
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