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JEE Mains · Physics · STD 11 - Fluid mechanics
  • JEE Mains 2024
  • Hard
  • MCQ

A cube of ice floats partly in water and partly in kerosene oil. The ratio of volume of ice immersed in water to that in kerosene oil is _______.(specific gravity of Kerosene oil \(=0.8\), specific gravity of ice \(=0.9\) )

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Answer & Solution

Correct Answer

(D)  \(1: 1\)

Step-by-step Solution

Detailed explanation

\(\mathrm{v}_1=\text { volume immersed in water. }\)

\(\mathrm{v}_2=\text { volume immersed in oil. }\)

\(\mathrm{v}_1 \rho_{\mathrm{w}} \mathrm{g}+\mathrm{v}_2 \rho_{\mathrm{o}} \mathrm{g}=\left(\mathrm{v}_1+\mathrm{v}_2\right) \rho_{\mathrm{c}} \mathrm{g}\)

\(\mathrm{v}_1+\frac{\mathrm{v}_2 \rho_0}{\rho_w}=\left(\mathrm{v}_1+\mathrm{v}_2\right) \frac{\rho_{\mathrm{c}}}{\rho_w}\)

\(=\mathrm{v}_1+0.8 \mathrm{v}_2=0.9 \mathrm{v}_1+0.9 \mathrm{v}_2\)

\(=0.1 \mathrm{v}_1=0.1 \mathrm{v}_2\)

\(\mathrm{v}_1: \mathrm{v}_2=1: 1\)

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