JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
An expression for a dimensionless quantity \(P\) is given by \(P=\frac{\alpha}{\beta} \log _{e}\left(\frac{ kt }{\beta x }\right)\); where \(\alpha\) and \(\beta\) are constants, \(x\) is distance ; \(k\) is Boltzmann constant and \(t\) is the temperature. Then the dimensions of \(\alpha\) will be
- A \([ M ^{0} L ^{-1} T ^{0} ]\)
- B \([ ML ^{0} T ^{-2}]\)
- C \([ MLT ^{-2}]\)
- D \([ ML ^{2} T ^{-2}]\)
Answer & Solution
Correct Answer
(C) \([ MLT ^{-2}]\)
Step-by-step Solution
Detailed explanation
\(P=\frac{\alpha}{\beta} \log _{ e }\left(\frac{ kt }{\beta x }\right)\) \(\frac{ kt }{\beta x }=1 \Rightarrow \beta=\frac{ kt }{ x }=\frac{ ML ^{2} T ^{-2}}{ L }\) \(\left(\because E =\frac{1}{2} kt \right)\) \(As \; P\) is dimensionless…
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