JEE Mains · Physics · STD 11 - 11. thermodynamics
Starting with the same initial conditions, an ideal gas expands from volume \(V_{1}\) to \(V_{2}\) in three different ways. The work done by the gas is \(W_{1}\) if the process is purely isothermal. \(W _{2}\). if the process is purely adiabatic and \(W _{3}\) if the process is purely isobaric. Then, choose the coned option
- A \(W _{1} < W _{2} < W _{3}\)
- B \(W _{2} < W _{3} < W _{1}\)
- C \(W _{3} < W _{1} < W _{2}\)
- D \(W _{2} < W _{1} < W _{3}\)
Answer & Solution
Correct Answer
(D) \(W _{2} < W _{1} < W _{3}\)
Step-by-step Solution
Detailed explanation
Area under curve is work \(W _{2} < W _{1} < W _{3}\)
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