Starting with the same initial conditions, an ideal gas expands from volume \(V_{1}\) to \(V_{2}\) in three different ways. The work done by the gas is \(W_{1}\) if the process is purely isothermal. \(W _{2}\). if the process is purely adiabatic and \(W _{3}\) if the process is purely isobaric. Then, choose the coned option

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Correct Answer

(D) \(W _{2} < W _{1} < W _{3}\)

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Area under curve is work

\(W _{2} < W _{1} < W _{3}\)

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