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JEE Mains · Physics · STD 11 - 3.2 motion in plane

Starting from the origin at time \(t=0,\) with initial velocity \(5 \hat{ j }\, ms ^{-1},\) a particle moves in the \(x-y\) plane with a constant acceleration of \((10 \hat{ i }+4 \hat{ j })\, ms ^{-2}\). At time \(t\), its coordinates are \(\left(20\, m , y _{0}\, m \right) .\) The values of \(t\) and \(y _{0},\) are respectively

  1. A \(4\, s\) and \(52\, m\)
  2. B \(2\, s\) and \(24\, m\)
  3. C \(2\,s\) and \(18\, m\)
  4. D \(5\, s\) and \(25\, m\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2\,s\) and \(18\, m\)

Step-by-step Solution

Detailed explanation

Given \(\quad \overrightarrow{ u }=5 \hat{ j } m / s , \overrightarrow{ a }=10 \hat{ i }+4 \hat{ j }, \quad\) final coordinate \(\left(20, y_{0}\right)\) in time \(t\) \(S_{x}=4 u_x \times {t}+\frac{1}{2} a_{x} t^{2}\) \(\frac{1}{2} \times 10 \times t^{2}\) \(t=2 \sec\)…
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