JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2015
- Medium
- Numerical
Assuming human pupil to have a radius of \(0.25\ cm\) and a comfortable viewing distance of \(25\ cm\), the minimum separation between two objects that human eye can resolve at \(500\ nm\) wavelength is.....\(\mu m\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(30\)
Step-by-step Solution
Detailed explanation
\(\sin \,\theta \, = \,\frac{{0.25}}{{25}}\, = \,\frac{1}{{100}}\)
Resolving power \( = \,\frac{{1.22\,\lambda }}{{2\,\mu \,\sin \,\theta }}\, = \,30\,\mu m\)
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