JEE Mains · Physics · STD 12 - 10. Wave optics
Assuming human pupil to have a radius of \(0.25\ cm\) and a comfortable viewing distance of \(25\ cm\), the minimum separation between two objects that human eye can resolve at \(500\ nm\) wavelength is.....\(\mu m\)
- A \(30\)
- B \(100\)
- C \(300\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(30\)
Step-by-step Solution
Detailed explanation
\(\sin \,\theta \, = \,\frac{{0.25}}{{25}}\, = \,\frac{1}{{100}}\) Resolving power \( = \,\frac{{1.22\,\lambda }}{{2\,\mu \,\sin \,\theta }}\, = \,30\,\mu m\)
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