JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A coil of circular cross-section having \(1000\, turns\) and \(4\, cm^2\) face area is placed with its axis parallel to a magnetic field which decreases by \(10^{-2}\, Wb\, m^{-2}\) in \(0.01\, s\). The \(e.m.f.\) induced in the coil is....\(mV\)
- A \(400\)
- B \(200\)
- C \(4\)
- D \(0.4\)
Answer & Solution
Correct Answer
(A) \(400\)
Step-by-step Solution
Detailed explanation
Given: \(Na\) of turns \(N=1000\) Face area, \(A=4 \,\mathrm{cm}^{2}=4 \times 10^{-4} \,\mathrm{m}^{2}\) Change in magnetic field, \(\Delta B=10^{-2} \,\mathrm{wbm}^{-2}\) Time taken, \(t=0.01\, \mathrm{s}=10^{-2}\, \mathrm{sec}\) \(Emf\) induced in the coil \(e=?\) Applying…
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