JEE Mains · Physics · STD 12 - Electric potential and capacitance
- JEE Mains 2019
- Medium
- MCQ
An electric field of \(1000\,V/m\) is applied to an electric dipole at angle of \(45^o\). The value of electric dipole moment is \(10^{-29}\, C.m.\) What is the potential energy of the electric dipole?
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \( - 7 \times {10^{-27}}\,J\)
Step-by-step Solution
Detailed explanation
\(U = - \vec P \cdot \vec E\)
\( = - PE\cos \theta \)
\( = - \left( {{{10}^{ - 29}}} \right)\left( {{{10}^3}} \right)\cos {45^\circ }\)
\( = - 0.707 \times {10^{ - 26}}\,{\text{J}}\)
\( = - 7 \times {10^{ - 27}}\,{\text{J}}\)
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