ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2022
  • Easy
  • MCQ

If the potential barrier across a \(p - n\) junction is \(0.6\,V\). Then the electric field intensity, in the depletion region having the width of \(6 \times 10^{-6} m\), will be \(......\times 10^{5} N / C\).

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(1\)

Step-by-step Solution

Detailed explanation

\(E =\frac{ V }{ d }=\frac{\text { Potential barrier Across Junction }}{\text { width of Depletion layer }}\)

\(=\frac{0.6\,V }{6 \times 10^{-6}\,m }=1 \times 10^{5}\,V / m\)

\(=1 \times 10^{5}\,N / C\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app