JEE Mains · Physics · STD 11 - 11. thermodynamics
The efficiency of an ideal heat engine working between the freezing point and boiling point of water, is ........ \(\%\)
- A \(26.8\)
- B \(20 \)
- C \(12.5\)
- D \(6.25\)
Answer & Solution
Correct Answer
(A) \(26.8\)
Step-by-step Solution
Detailed explanation
Efficiency of an ideal heat engine, \(\eta = \left( {1 - \frac{{{T_2}}}{{{T_1}}}} \right)\) Freezing point of water \( = {0^ \circ }C = 273\,K\) Boiling point of water\( = {100^ \circ }C = \left( {100 + 273} \right)K\) \( = 373\,K\) \(T_2\) Sink temperature\(=273 K\) \(T_1\)…
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