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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2026
  • Easy
  • MCQ

Two resistors of \(100 \Omega\) each are connected in series with a 9 V battery. A voltmeter of \(400 \Omega\) resistance is connected to measure the voltage drop across one of the resistors. The voltmeter reading is _________ V.

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Answer & Solution

Correct Answer

(C) 4

Step-by-step Solution

Detailed explanation


image
Current in circuit.
\(I=\frac{E}{\operatorname{Req}}\)
Req \(=100+\frac{400 \times 100}{400+100}=180 \Omega\)
\(\therefore I =\frac{9}{180}=\frac{1}{20} A\)
Reading of voltmeter \(= V = I \times 80=\frac{1}{20} \times 80=4 V\)
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