JEE Mains · Physics · STD 11 - 3.1 vectors
Three particles \({P}, {Q}\) and \({R}\) are moving along the vectors \({A}=\hat{{i}}+\hat{{j}}, {B}=\hat{{j}}+\hat{{k}}\) and \({C}=-\hat{{i}}+\hat{{j}}\) respectively. They strike on a point and start to move in different directions. Now particle \(P\) is moving normal to the plane which contains vector \(\vec{A}\) and \(\vec{B} .\) Similarly particle \(Q\) is moving normal to the plane which contains vector \(\vec{A}\) and \(\vec{C} .\) The angle between the direction of motion of \(P\) and \(Q\) is \(\cos ^{-1}\left(\frac{1}{\sqrt{x}}\right)\). Then the value of \(x\) is ...... .
- A \(11\)
- B \(47\)
- C \(5\)
- D \(3\)
Answer & Solution
Correct Answer
(D) \(3\)
Step-by-step Solution
Detailed explanation
Direction of \(P=\hat{v}_{1}=\pm \frac{\vec{A} \times \vec{B}}{|\vec{A} \times \vec{B}|}=\pm \frac{\hat{i}-\hat{j}+\hat{k}}{\sqrt{3}}\) Direction of \(Q=\hat{v}_{2}=\pm \frac{\vec{A} \times \vec{C}}{|\vec{A} \times \vec{C}|}=\pm \frac{2 \hat{k}}{2}=\pm \hat{k}\) Angle between…
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