JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
There is a small source of light at some depth below the surface of water (refractive index \(=\frac{4}{3}\) ) in a tank of large cross sectional surface area. Neglecting any reflection from the bottom and absorption by water, percentage of light that emerges out of surface is (nearly)...........\(\%\) [Use the fact that surface area of a spherical cap of height \(\mathrm{h}\) and radius of curvature \(\mathrm{r} \text { is } 2 \pi \mathrm{rh}]\)
- A \(17\)
- B \(21\)
- C \(34\)
- D \(50\)
Answer & Solution
Correct Answer
(A) \(17\)
Step-by-step Solution
Detailed explanation
\(\frac{4}{3} \sin \theta=1 \sin 90^{\circ}\) \(\sin \theta=\frac{3}{4}\) Area of sphere in which light spread \(=4 \pi \mathrm{R}^{2}\) \(\Omega=2 \pi(1-\cos \theta)\) \(\Omega=2 \pi\left(1-\frac{\sqrt{7}}{4}\right)\) \(\mathrm{P} \rightarrow 4 \pi\) steradians…
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