JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
A particle of mass \(m\) is moving along the \(x\) -axis with initial velocity \(u \hat i\). It collides elastically with a particle of mass \(10\, m\) at rest and then moves with half its initial kinetic energy (see figure). If \(\sin \theta_{1}=\sqrt{n} \sin \theta_{2}\) then value of \(n\) is.....
- A \(20\)
- B \(26\)
- C \(10\)
- D \(15\)
Answer & Solution
Correct Answer
(C) \(10\)
Step-by-step Solution
Detailed explanation
By momentum conservation along \(y\) \(m _{1} u _{1} \sin \theta_{1}= m _{2} u _{2} \sin \theta_{2}\) i.e. \(mu _{1} \sin \theta_{1}=10 mu _{2} \sin \theta_{2}\) \(\Rightarrow u _{1} \sin \theta_{1}=10 u _{2} \sin \theta_{2}\) \(...(i)\)…
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