JEE Mains · Physics · STD 12 - 10. Wave optics
In a Young's double slits experiment, the ratio of amplitude of light coming from slits is \(2: 1\). The ratio of the maximum to minimum intensity in the interference pattern is :
- A \(9: 4\)
- B \(9: 1\)
- C \(2: 1\)
- D \(25: 9\)
Answer & Solution
Correct Answer
(B) \(9: 1\)
Step-by-step Solution
Detailed explanation
Given that \(\frac{ A _1}{ A _2}=\frac{2}{1}\) \(\frac{I_{\max }}{I_{\min }}=\left(\frac{ A _1+ A _2}{ A _1- A _2}\right)^2=\frac{9}{1}=9: 1\)
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