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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2023
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  • MCQ

In a Young's double slits experiment, the ratio of amplitude of light coming from slits is \(2: 1\). The ratio of the maximum to minimum intensity in the interference pattern is :

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Answer & Solution

Correct Answer

(B) \(9: 1\)

Step-by-step Solution

Detailed explanation

Given that \(\frac{ A _1}{ A _2}=\frac{2}{1}\)

\(\frac{I_{\max }}{I_{\min }}=\left(\frac{ A _1+ A _2}{ A _1- A _2}\right)^2=\frac{9}{1}=9: 1\)

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