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JEE Mains · Physics · STD 12 - Atoms
  • JEE Mains 2022
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  • MCQ

Given below are two statements: Statement \(I\) : In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit \(\left( E _{1}\right)\) to higher energy orbit \(\left( E _{2}\right)\), is given as \(hf = E _{1}- E _{2}\). Statement \(II\) : The jumping of electron from higher energy orbit \(\left(E_{2}\right)\) to lower energy orbit \(\left(E_{1}\right)\) is associated with frequency of radiation given as \(f\) \(=\left( E _{2}- E _{1}\right) / h\) This condition is Bohr's frequency condition. In the light of the above statements, choose the correct answer from the options given below

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Answer & Solution

Correct Answer

(D) Statement \(I\) is incorrect but statement \(II\) is true

Step-by-step Solution

Detailed explanation

When electron jump from lower to higher energy level, energy absorbed so statement - \(I\) incorrect. When electron jump from higher to lower energy level, energy of emitted photon

\(E = E _{2}- E _{1}\)

\(hf = E _{2}- E _{1} \Rightarrow f =\frac{ E _{2}- E _{1}}{ h }\)

so statement - \(II\) is correct.

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