JEE Mains · Physics · STD 11 - 14. waves and sound
A transverse wave on a string is described by \(y = 3\sin(36t + 0.018x + \pi/4)\), where \(x, y\) are in cm and \(t\) in seconds. The least distance between the two successive crests in the wave is _____ cm. (Nearest integer)
(\(\pi = 3.14\))
- A 349
- B 379
- C 385
- D 394
Answer & Solution
Correct Answer
(A) 349
Step-by-step Solution
Detailed explanation
The standard equation of a transverse wave is given by \(y = A\sin(\omega t + kx + \phi)\) Comparing this with the given equation \(y = 3\sin(36t + 0.018x + \pi/4)\), we get the wave number \(k = 0.018 \text{ cm}^{-1}\). The least distance between two successive crests is the…
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