JEE Mains · Physics · STD 11 - 13. oscillations
In the given figure, a body of mass \(M\) is held between two massless springs, on a smooth inclined plane. The free ends of the springs are attached to firm supports. If each spring has spring constant \(k,\) the frequency of oscillation of given body is :

- A \(\frac{1}{2 \pi} \sqrt{\frac{ k }{2 M }}\)
- B \(\frac{1}{2 \pi} \sqrt{\frac{2 k }{ Mg \sin \alpha}}\)
- C \(\frac{1}{2 \pi} \sqrt{\frac{2 k }{ M }}\)
- D \(\frac{1}{2 \pi} \sqrt{\frac{ k }{ Mg \sin \alpha}}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2 \pi} \sqrt{\frac{2 k }{ M }}\)
Step-by-step Solution
Detailed explanation
\(K _{ eq }= K _{1}+ K _{2}= K + K =2 K\) \(T =2 \pi \sqrt{\frac{ m }{ K _{ eq }}}=2 \pi \sqrt{\frac{ m }{2 K }}\) \(f =\frac{1}{ T }=\frac{1}{2 \pi} \sqrt{\frac{2 K }{ m }}\)
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