JEE Mains · Physics · STD 12 - 3. current electricity
A potentiometer wire of length \(10 \,m\) and resistance\(20 \,\Omega\) is connected in series with a \(25 \,V\) battery and an external resistance \(30\, \Omega\). A cell of emf \(E\) in secondary circuit is balanced by \(250\, cm\) long potentiometer wire. The value of \(E\) (in volt) is \(\frac{x}{10}\). The value of \(x\) is.......
- A \(56\)
- B \(85\)
- C \(25\)
- D \(55\)
Answer & Solution
Correct Answer
(C) \(25\)
Step-by-step Solution
Detailed explanation
\(I =\frac{25}{50}=\frac{1}{2} \,A\) \(\therefore \Delta\, V =10 \,V\) \(10 \,m \rightarrow 10 \,V\) \(2.5\, m \rightarrow 2.5\, V\)
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