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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2023
  • Medium
  • Numerical

Two identical cells each of emf \(1.5\,V\) are connected in series across a \(10\,\Omega\) resistance. An ideal voltmeter connected across \(10\,\Omega\) resistance reads \(1.5\,V\). The internal resistance of each cell is \(......\Omega\).

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Answer & Solution

Correct Answer

(A) \(5\)

Step-by-step Solution

Detailed explanation

\(V = I \times 10\)

\(1.5=\left(\frac{3}{10+2 r }\right) \times 10\)

\(r =5\,\Omega\)

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