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JEE Mains · Physics · STD 11 - 13. oscillations

In the given figure, a mass \(M\) is attached to a horizontal spring which is fixed on one side to a rigid support. The spring constant of the spring is \(k\). The mass oscillates on a frictionless surface with time period \(T\) and amplitude \(A\). When the mass is in equilibrium position, as shown in the figure, another mass \(m\) is gently fixed upon it. The new amplitude of oscillation will be

  1. A \(A \sqrt{\frac{M-m}{M}}\)
  2. B \(A \sqrt{\frac{M}{M+m}}\)
  3. C \(A \sqrt{\frac{M+m}{M}}\)
  4. D \(A \sqrt{\frac{M}{M-m}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(A \sqrt{\frac{M}{M+m}}\)

Step-by-step Solution

Detailed explanation

Momentum of system remains conserved. \(p_{i}=p_{i}\) \(MA \omega=( m + M ) A ^{\prime} \omega^{\prime}\) \(M A \sqrt{\frac{k}{M}}=(m+M) A^{\prime} \sqrt{\frac{k}{m+M}}\) \(A ^{\prime}= A \sqrt{\frac{ M }{ M + m }}\)
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