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JEE Mains · Physics · STD 11- Mechanical properties of solids
  • JEE Mains 2019
  • Medium
  • MCQ

The elastic limit of brass is \(379\,MPa.\) .......... \(mm\) should be the minimum diameter of a brass rod if it is to support a \(400\,N\) load without exceeding its elastic limit .

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Answer & Solution

Correct Answer

(B) \(1.16\)

Step-by-step Solution

Detailed explanation

\(\frac{{400}}{{\frac{\pi }{4}{d^2}}} = 379 \times {10^6}\)

\({d^2} = \frac{{4 \times 400 \times {{10}^{ - 6}}}}{{\pi  \times 379}} = 0.336 \times {10^{ - 6}} \times 4\)

\(d = 2\sqrt {0.336}  \times {10^{ - 3}}M \simeq 1.16\,mm\)

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