JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2021
- Easy
- Numerical
In a semiconductor, the number density of intrinsic charge carriers at \(27^{\circ} {C}\) is \(1.5 \times 10^{16} \,/ {m}^{3}\). If the semiconductor is doped with impurity atom, the hole density increase to \(4.5 \times 10^{22}\, / {m}^{3}\). The electron density in the doped semiconductor is \(.....\,\times 10^{9} / {m}^{3}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
\(n _{ e } n _{ h }= n _{ i }^{2}\)
\(n _{ e }=\frac{ n _{ i }^{2}}{ n _{ h }}=\frac{\left(1.5 \times 10^{16}\right)^{2}}{4.5 \times 10^{22}}\)
\(=\frac{1.5 \times 1.5 \times 10^{32}}{4.5 \times 10^{22}}\)
\(5 \times 10^{9} / m ^{3}\)
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