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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2021
  • Easy
  • Numerical

In a semiconductor, the number density of intrinsic charge carriers at \(27^{\circ} {C}\) is \(1.5 \times 10^{16} \,/ {m}^{3}\). If the semiconductor is doped with impurity atom, the hole density increase to \(4.5 \times 10^{22}\, / {m}^{3}\). The electron density in the doped semiconductor is \(.....\,\times 10^{9} / {m}^{3}\)

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Answer & Solution

Correct Answer

(A) \(5\)

Step-by-step Solution

Detailed explanation

\(n _{ e } n _{ h }= n _{ i }^{2}\)

\(n _{ e }=\frac{ n _{ i }^{2}}{ n _{ h }}=\frac{\left(1.5 \times 10^{16}\right)^{2}}{4.5 \times 10^{22}}\)

\(=\frac{1.5 \times 1.5 \times 10^{32}}{4.5 \times 10^{22}}\)

\(5 \times 10^{9} / m ^{3}\)

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